by VB-Kung-Fu (19 Submissions)
Category: String Manipulation
Compatability: VB 6.0
Difficulty: Unknown Difficulty
Originally Published: Thu 9th October 2003
Date Added: Mon 8th February 2021
Rating: 
(1 Votes)
Returns a space delimited list of ASCII codes that would be needed to convert a number to its string represtantion.
VBcoders
Dim Digit As Variant, div As Long
If IsNumeric(Num) = False Then Exit Function
div = 1000000000
'ensure num is positive before working but include negative sign
'if num is negative
If Num < 0 Then
Num = Num * -1
Dec2Ascii = CStr(Asc("-"))
ElseIf Num < 10 Then
Dec2Ascii = CStr(Num Or 48)
Exit Function
End If
'this following process extracts each individual digit
'in the number and produces its ascii code
Do While div > 0 And Num > 0
If Num >= div Then
'extract digit
Digit = Num \ div
'the ORing with 48 converts the binary values for 0 - 9 to their
'ascii code. eg 5 or 48 = 53 which is the ascii code for 5
Dec2Ascii = Dec2Ascii & " " & (Digit Or 48)
If Num Mod div = 0 Then
'if the number is a multiple of ten we have to use this method in
'order to get the zeros in
Do While Num > 10
Dec2Ascii = Dec2Ascii & " " & Asc("0")
Num = Num / 10
Loop
Exit Function
End If
Num = Num Mod div 'move to next digit
End If
div = div / 10 'decrease the divisor since number is too small
Loop
Dec2Ascii = RTrim(Dec2Ascii)
End Function
No comments have been posted about Returns a space delimited list of ASCII codes that would be needed to convert a number to its strin. Why not be the first to post a comment about Returns a space delimited list of ASCII codes that would be needed to convert a number to its strin.
