by Salvatore Pece- Paradox Systems Solutions (1 Submission)
Category: String Manipulation
Compatability: Visual Basic 5.0
Difficulty: Unknown Difficulty
Originally Published: Tue 30th May 2000
Date Added: Mon 8th February 2021
Rating: 
(1 Votes)
This code will easily break a multiline text box into a string array. It works much easier than all others found on the net so far. Enjoy.
API Declarations
Dim multi(12) As String
VBcoders
'Other than that, here you go. This will store the broken apart strings into
'the multi array. You can change the size if you like, could probably even do
'it dynamically if needed.
Private Function convertText(str As String, maxLen As Integer)
Dim strCount As Integer
Dim pos As Long
Dim endPos As Long
Dim tempStr As String
strCount = 0
pos = 1
While pos < Len(str)
strCount = strCount + 1
If Len(Mid(str, pos)) - 1 > maxLen Then
'The lenght of the remaining string is greater
'than the maximum lenght then
If InStr(pos, str, vbCr) > (maxLen + pos) Then
'An enter character was found but it exceeded
'The length
If InStr(pos, str, " ") = (maxLen + pos) Then
'If there is a blank at the proper
'position then set the string
multi(strCount) = Mid(str, pos, maxLen)
pos = pos + maxLen
Else
'Must work backwards until a space
'is found
If InStr(pos, str, " ") > (pos + maxLen) Then
'If the string's space is after the
'maximum length then cut the string
multi(strCount) = Mid(str, pos, maxLen)
pos = pos + maxLen
Else
'Work back words from the position
endPos = maxLen
While Not (Mid(str, endPos, 1) = " ")
endPos = endPos - 1
Wend
multi(strCount) = Mid(str, pos, endPos)
pos = pos + endPos
End If
End If
ElseIf InStr(pos, str, vbCr) < (maxLen + pos) And (InStr(pos, str, vbCr) > 1) Then
'if enter character found
'from a string less than maxlen
multi(strCount) = Mid(str, pos, (InStr(pos, str, vbCr) - pos))
pos = InStr(pos, str, vbCr) + 2
Else
'This would be if no enter signs were encountered
If InStr(pos, str, " ") > (pos + maxLen) Then
'If the string's space is after the
'maximum length then cut the string
multi(strCount) = Mid(str, pos, maxLen)
pos = pos + maxLen
ElseIf InStr(pos, str, " ") < (pos + maxLen) Then
'Work back words from the position
endPos = maxLen
While (Not (Mid(str, endPos, 1) = " "))
endPos = endPos - 1
Wend
multi(strCount) = Mid(str, pos, endPos)
pos = pos + endPos
Else
MsgBox ("Some condition wasn't met")
End If
End If
Else
While pos < Len(str)
If InStr(pos, str, vbCr) Then
tempStr = Mid(str, pos, InStr(pos, str, vbCr) - pos)
multi(strCount) = tempStr
pos = InStr(pos, str, vbCr) + 2
Else
multi(strCount) = Mid(str, pos, Len(str))
pos = Len(str)
End If
Wend
End If
Wend
End Function
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