by Best Programmer (4 Submissions)
Category: Databases/Data Access/DAO/ADO
Compatability: Visual Basic 5.0
Difficulty: Unknown Difficulty
Originally Published: Thu 24th May 2001
Date Added: Mon 8th February 2021
Rating: 
(1 Votes)
This code takes values entered into a textbox enters them into a listbox and then plots them on a line Graph. In this case a Picture box.
API Declarations
'Just add two textboxes: TxtNumber and TxtScore
'Three command buttons: cmdEnter, cmdClear and cmdExit
'Draw a picture box with the dimensions of Height: 2535 and Width of 3015
Dim X As Single, Y As Single
Dim n As Integer
Dim NewPointX As Integer, NewPointY As Integer
Dim LastPointX As Integer, LastPointY As Integer
'and Enjoy
VBcoders
Private Sub cmdClear_Click()
txtNumber = ""
txtScore = ""
LineGraph.Cls
ListScore.Clear
txtNumber.SetFocus
End Sub
Private Sub cmdClearValues_Click()
txtScore = ""
txtNumber = ""
txtNumber.SetFocus
End Sub
Private Sub cmdEnterData_Click()
ListScore.AddItem Val(txtNumber) & " " & Val(txtScore)
NewPointX = Val(txtNumber) * 50
NewPointY = 2535 - (Val(txtScore) * 20)
LineGraph.Line (LastPointX, LastPointY)-(NewPointX, NewPointY)
LastPointX = NewPointX
LastPointY = NewPointY
txtScore = ""
txtNumber = ""
txtNumber.SetFocus
'n = n + 1
End Sub
Private Sub cmdExit_Click()
End
End Sub
Private Sub Form_Load()
n = 0
LastPointX = 0
LastPointY = 2535
End Sub
Private Sub txtScore_KeyPress(KeyAscii As Integer)
If KeyAscii = 13 Then
ListScore.AddItem Val(txtNumber) & " " & Val(txtScore)
NewPointX = Val(txtNumber) * 50
NewPointY = 2535 - (Val(txtScore) * 20)
LineGraph.Line (LastPointX, LastPointY)-(NewPointX, NewPointY)
LastPointX = NewPointX
LastPointY = NewPointY
txtScore = ""
txtNumber = ""
txtNumber.SetFocus
n = n + 1
End If
End Sub
No comments have been posted about This code takes values entered into a textbox enters them into a listbox and then plots them on a l. Why not be the first to post a comment about This code takes values entered into a textbox enters them into a listbox and then plots them on a l.
