by Dalin Nie (5 Submissions)
Category: Windows API Call/Explanation
Compatability: Visual Basic 4.0 (32-bit)
Difficulty: Unknown Difficulty
Originally Published: Mon 19th April 1999
Date Added: Mon 8th February 2021
Rating: 
(1 Votes)
This code make a transparent area of different shape(such as Rectangle, Circle) so you can not only see through it, and acturally access the
VBcoders
Private Declare Function CreateRoundRectRgn Lib "gdi32" (ByVal X1 As Long, ByVal Y1 As Long, ByVal X2 As Long, ByVal Y2 As Long, ByVal X3 As Long, ByVal Y3 As Long) As Long
Private Declare Function CreateRectRgn Lib "gdi32" (ByVal X1 As Long, ByVal Y1 As Long, ByVal X2 As Long, ByVal Y2 As Long) As Long
Private Declare Function CreateEllipticRgn Lib "gdi32" (ByVal X1 As Long, ByVal Y1 As Long, ByVal X2 As Long, ByVal Y2 As Long) As Long
Private Declare Function CombineRgn Lib "gdi32" (ByVal hDestRgn As Long, ByVal hSrcRgn1 As Long, ByVal hSrcRgn2 As Long, ByVal nCombineMode As Long) As Long
Private Declare Function SetWindowRgn Lib "user32" (ByVal hWnd As Long, ByVal hRgn As Long, ByVal bRedraw As Long) As Long
'2 The Forction
Private Function fMakeATranspArea(AreaType As String, pCordinate() As Long) As Boolean
'Name: fMakeATranpArea
'Author: Dalin Nie
'Date: 5/18/98
'Purpose: Create a Transprarent Area in a form so that you can see through
'Input: Areatype : a String indicate what kind of hole shape it would like to make
' PCordinate : the cordinate area needed for create the shape:
' Example: X1, Y1, X2, Y2 for Rectangle
'OutPut: A boolean
Const RGN_DIFF = 4
Dim lOriginalForm As Long
Dim ltheHole As Long
Dim lNewForm As Long
Dim lFwidth As Single
Dim lFHeight As Single
Dim lborder_width As Single
Dim ltitle_height As Single
On Error GoTo Trap
lFwidth = ScaleX(Width, vbTwips, vbPixels)
lFHeight = ScaleY(Height, vbTwips, vbPixels)
lOriginalForm = CreateRectRgn(0, 0, lFwidth, lFHeight)
lborder_width = (lFHeight - ScaleWidth) / 2
ltitle_height = lFHeight - lborder_width - ScaleHeight
Select Case AreaType
Case "Elliptic"
ltheHole = CreateEllipticRgn(pCordinate(1), pCordinate(2), pCordinate(3), pCordinate(4))
Case "RectAngle"
ltheHole = CreateRectRgn(pCordinate(1), pCordinate(2), pCordinate(3), pCordinate(4))
Case "RoundRect"
ltheHole = CreateRoundRectRgn(pCordinate(1), pCordinate(2), pCordinate(3), pCordinate(4), pCordinate(5), pCordinate(6))
Case "Circle"
ltheHole = CreateRoundRectRgn(pCordinate(1), pCordinate(2), pCordinate(3), pCordinate(4), pCordinate(3), pCordinate(4))
Case Else
MsgBox "Unknown Shape!!"
Exit Function
End Select
lNewForm = CreateRectRgn(0, 0, 0, 0)
CombineRgn lNewForm, lOriginalForm, _
ltheHole, RGN_DIFF
SetWindowRgn hWnd, lNewForm, True
Me.Refresh
fMakeATranspArea = True
Exit Function
Trap:
MsgBox "error Occurred. Error # " & Err.Number & ", " & Err.Description
End Function
' 3'To Call
Dim lParam(1 To 6) As Long
lParam(1) = 100
lParam(2) = 100
lParam(3) = 250
lParam(4) = 250
lParam(5) = 50
lParam(6) = 50
'Call fMakeATranspArea("RoundRect", lParam())
'Call fMakeATranspArea("RectAngle", lParam())
Call fMakeATranspArea("Circle", lParam())
'Call fMakeATranspArea("Elliptic", lParam())
No comments have been posted about This code make a transparent area of different shape(such as Rectangle, Circle) so you can not only. Why not be the first to post a comment about This code make a transparent area of different shape(such as Rectangle, Circle) so you can not only.
