by Cyrus Lacaba aka Biohazard of Las Pi?as (6 Submissions)
Category: Math/Dates
Compatability: VB.NET
Difficulty: Unknown Difficulty
Originally Published: Fri 17th July 2009
Date Added: Mon 8th February 2021
Rating: 
(1 Votes)
Structured Rounding of Numbers equivalent to Round Function of VB6. Mostly used in Microsoft Access... Enjoy
VBcoders
On Error GoTo RoundNoErr
Dim strValue$, strValue2$, intstrValuelength%, intNextValue%, strValuetoAdd$, intValLength%, ix%
strValue$ = CStr(Val(fltValue))
intValLength% = intDecimalPlaces + 2
If intDecimalPlaces = 0 Then
Dim intFixValue%
intFixValue% = Fix(Val(fltValue))
strValue2$ = Mid(strValue$, 3)
If Val(Mid(strValue2$, 1, 1)) >= 5 Then
RoundNo = intFixValue% + 1
Else
RoundNo = intFixValue%
End If
Exit Function
ElseIf (intValLength% = Len(strValue$)) Or _
(strValue$ = "0.0" Or strValue$ = "0") Or _
(intDecimalPlaces < 0) Then
strValue2$ = strValue$
GoTo ReturnTheSameValue
End If
strValue2$ = Mid(strValue$, 1, intValLength%)
intNextValue% = Val(Mid(strValue$, intValLength% + 1, 1))
If intNextValue% >= 5 Then
intstrValuelength% = Len(strValue2$)
strValuetoAdd$ = "0."
For ix = 3 To intstrValuelength%
If ix = intstrValuelength% Then Exit For
strValuetoAdd$ = strValuetoAdd$ & "0"
Next
strValuetoAdd$ = strValuetoAdd$ & "1"
RoundNo = CDbl(strValue2$) + CDbl(strValuetoAdd$)
Else
GoTo ReturnTheSameValue
End If
Exit Function
ReturnTheSameValue:
RoundNo = CDbl(strValue2$)
Exit Function
RoundNoErr:
RoundNo = 0
End Function
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