by Leigh Bowers (6 Submissions)
Category: String Manipulation
Compatability: Visual Basic 3.0
Difficulty: Unknown Difficulty
Date Added: Wed 3rd February 2021
Rating: 
(8 Votes)
This code is a direct replacement for the VB6 Replace function. Obviously, VB 6 users will have very little (if any) use for the function. It is intended for use with older versions of VB that do not have the in-built Replace function. I noticed a similar piece of code released earlier this week, but it only appeared to handle character replacing and not strings. This version will do both and it's pretty tight and fast.
VBcodersPublic Function Replace(sExpression As String, sFind As String, sReplace As String) As String
' Title: Replace
' Version: 1.01
' Author: Leigh Bowers
' WWW: http://www.esheep.freeserve.co.uk/compulsion
Dim lPos As Long
Dim iFindLength As Integer
' Ensure we have all required parameters
If Len(sExpression) = 0 Or Len(sFind) = 0 Then
Exit Function
End If
' Determine the length of the sFind variable
iFindLength = Len(sFind)
' Find the first instance of sFind
lPos = InStr(sExpression, sFind)
' Process and find all subsequent instances
Do Until lPos = 0
sExpression = Left$(sExpression, lPos - 1) + sReplace + Mid$(sExpression, lPos + iFindLength)
lPos = InStr(lPos, sExpression, sFind)
Loop
' Return the result
Replace = sExpression
End Function