by KRYO_11 (20 Submissions)
Category: String Manipulation
Compatability: Visual Basic 5.0
Difficulty: Intermediate
Date Added: Wed 3rd February 2021
Rating: 
(7 Votes)
Includes many common useful string functions. Reverse string, Remove extra spaces, Delimit string, Alternating caps, Proper case, and Count number of occurances of a string in a string. Vote if you like it!
VBcodersPublic Function ReverseString(TheString As String) As String
ReverseString = ""
For i = 0 To Len(TheString) - 1
ReverseString = ReverseString & Mid(TheString, Len(TheString) - i, 1)
Next i
End Function
Public Function RemoveExtraSpaces(TheString As String) As String
Dim LastChar As String
Dim NextChar As String
LastChar = Left(TheString, 1)
RemoveExtraSpaces = LastChar
For i = 2 To Len(TheString)
NextChar = Mid(TheString, i, 1)
If NextChar = " " And LastChar = " " Then
Else
RemoveExtraSpaces = RemoveExtraSpaces & NextChar
End If
LastChar = NextChar
Next i
End Function
Public Function DelimitString(TheString As String, Delimiter As String) As String
DelimitString = ""
For i = 1 To Len(TheString)
If i <> Len(TheString) Then
DelimitString = DelimitString & Mid(TheString, i, 1) & Delimiter
Else
DelimitString = DelimitString & Mid(TheString, i, 1)
End If
Next i
End Function
Public Function AltCaps(TheString As String, Optional StartWithFirstCharacter As Boolean = True) As String
Dim LastCap As Boolean
AltCaps = ""
If StartWithFirstCharacter = False Then LastCap = True
For i = 1 To Len(TheString)
If LastCap = False Then
AltCaps = AltCaps & UCase(Mid(TheString, i, 1))
LastCap = True
Else
AltCaps = AltCaps & LCase(Mid(TheString, i, 1))
LastCap = False
End If
Next i
End Function
Public Function Propercase(TheString As String) As String
Propercase = UCase(Left(TheString, 1))
For i = 2 To Len(TheString)
If Mid(TheString, i - 1, 1) = " " Then
Propercase = Propercase & UCase(Mid(TheString, i, 1))
Else
Propercase = Propercase & LCase(Mid(TheString, i, 1))
End If
Next i
End Function
Public Function CountCharacters(TheString As String, CharactersToCheckFor As String) As Integer
Dim Char As String
Dim ReturnAgain As Boolean
CountCharacters = 0
For i = 1 To Len(TheString)
If i < (Len(TheString) + 1 - Len(CharactersToCheckFor)) Then
Char = Mid(TheString, i, Len(CharactersToCheckFor))
ReturnAgain = True
Else
Char = Mid(TheString, i)
ReturnAgain = False
End If
If Char = CharactersToCheckFor Then CountCharacters = CountCharacters + 1
If ReturnAgain = False Then GoTo NextPos
Next i
NextPos:
End Function
