by Darrin (1 Submission)
Category: VB function enhancement
Compatability: Visual Basic 3.0
Difficulty: Beginner
Date Added: Wed 3rd February 2021
Rating: 
(3 Votes)
This code will autofill a textbox from a database table using the keyup event.
Inputs
User input into textbox and database via ADODB recordset.
Code Returns
It will autofill the textbox with the the first match of the letters the user types in.
Side Effects
I used the keyup event to keep it very simple, although if a user types quickly, and presses a key before the previous key is released (keyup'd), it will cause and error and clear the textbox.
API DeclarationsPlace the variables that are in ALL CAPS as global variables, and set STRNAME = "" and the INTPLACE = 0 on the GotFocus and the LostFocus events of the textbox.
You will also need to set "cn" = to an ADODB connection to your database.
VBcodersPrivate Sub Textbox1_KeyUp(KeyCode As Integer, Shift As Integer)
Dim rsTable as ADODB.recordset
Set rsTable = New ADODB.recordset
On Error GoTo ENDOFSUB
rsTable.Open "Select * from TABLE", cn, adopenstatic, adlockoptomistic
STRWORD = Me.textbox1.Text
If Len(STRWORD) < INTPLACE Then
INTPLACE = Len(STRWORD) - 1
End If
If KeyCode = vbKeyBack Or KeyCode = vbKeyLeft Then
If INTPLACE > 0 Then
INTPLACE = INTPLACE - 1
STRWORD = Mid(STRWORD, 1, Len(STRWORD) - 1)
End If
ElseIf Me.textbox1.Text = "" Then
INTPLACE = 0
STRWORD = ""
ElseIf KeyCode <> vbKeyDelete And KeyCode <> vbKeyShift Then
INTPLACE = INTPLACE + 1
STRWORD = STRWORD & Chr(KeyCode)
End If
rsTable.MoveFirst
If Me.textbox1.Text <> "" Then
Do While Not rsTable.EOF
If Mid(Trim(rsTable!Field1), 1, INTPLACE) = UCase(Mid(Me.textbox1.Text, 1, INTPLACE)) Then
Me.textbox1.Text = Trim(rsTable!Field1)
Exit Do
End If
m_rsEmployee.MoveNext
Loop
End If
If KeyCode <> vbKeyShift Then
Me.textbox1.SelStart = INTPLACE
Me.textbox1.SelLength = (Len(Me.textbox1.Text)) - INTPLACE
End If
Exit Sub
ENDOFSUB:
Me.textbox1.Text = ""
INTPLACE = 0
End Sub
