How to extract a file name from one path.

by Iratxe Bajo Urcelay (3 Submissions)
Category: String Manipulation
Compatability: VB 6.0
Difficulty: Unknown Difficulty
Originally Published: Wed 20^th November 2002
Date Added: Mon 8^th February 2021
Rating: (1 Votes)

API Declarations
Dim i As Integer

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commonDialog1.ShowOpen
nameFile = Mid$(commonDialog1.FileName, 4) 'removes "C:\"
Do
    If InStr(1, nameFile, "\") Then 'verifies if there is any "\"
    'Yes. It does exist "\"
        i = InStr(1, nameFile, "\")
        nameFile = Mid$(nameFile, i + 1)
    End If
Loop Until InStr(1, nameFile, "\") = False

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