by Dipen Anovadia (19 Submissions)
Category: Custom Controls/Forms/Menus
Compatability: Visual Basic 5.0
Difficulty: Unknown Difficulty
Originally Published: Sun 21st August 2005
Date Added: Mon 8th February 2021
Rating: 
(1 Votes)
Gets the ListIndex number from given Text in given ComboBox with starting and ending position specified
VBcoders
'and ending to given values for any ComboBox
'IN: cb > ComboBox from which index is to be searched
' sTxt > Text to search in ComboBox
' lStart > Starting position (0 = From First)
' lEnd > Ending position (<0 is ComboBox.ListCount)
'OUT: lIDReturn > The ListIndex value which was found
'Return: True for success else False
'Tip: If Return is False and lIDReturn <> -1 Then lIDReturn
' is the error number, so that you can display error
' message later on if you wish.
Public Function IndexFromText( _
cb As ComboBox, sTxt As String, _
lIDReturn As Long, lStart As Long, _
lEnd As Long) As Boolean
'Handle the error to avoid illegal termination of program
On Error GoTo errIFT
'Variable declaration
Dim l As Long, lBegin As Long, lFinish As Long
Dim sItem As String, lCurID As Long
Dim lStep As Long, lCount As Long
'Initialization
IndexFromText = False
lIDReturn = -1
lBegin = lStart: lFinish = lEnd
lCount = cb.ListCount - 1
'Validating starting and ending position
If lBegin < 0 Then lBegin = 0
If lFinish > lCount Then lFinish = lCount
If lFinish < 0 Then lFinish = lCount
'Priority-wise
If lBegin > lFinish Then lStep = -1 Else lStep = 1
'Loop for verification
l = 0
For l = lBegin To lFinish Step lStep
sItem = cb.List(l)
If sItem = sTxt Then
IndexFromText = True
lIDReturn = l
Exit Function
End If
Next l
Exit Function
'Reply the error and failure both at a time
errIFT:
lRetVal = Err.Number
IndexFromText = False
Err.Clear
Exit Function
End Function
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