by Guy Parrulli (1 Submission)
Category: Miscellaneous
Compatability: VB 6.0
Difficulty: Unknown Difficulty
Originally Published: Sun 7th April 2002
Date Added: Mon 8th February 2021
Rating: 
(1 Votes)
Finds the date of N number of work days out and excludes any holidays you pass in.
VBcoders
Private Sub Command1_Click()
Dim holidays
holidays = Array("7/4/2002", "9/2/2002")
Text2.Text = DateAddWorkDays("7/2/2002", 8, holidays)
End Sub
'
'' Send in an array of Holiday Dates to skip as workdays in the ListOFHolidays variant
Private Function DateAddWorkDays(ByVal StartDate As Date, ByVal HowManyWorkDays As Long, Optional ListofHolidays As Variant) As Date
Dim CountOFHolidays As Long
Dim CountOFWorkdays As Long
Dim countofWeekEnds As Long
Dim DateInQuestion As Date
Dim AddOrSubtract As Long
Dim isholiday As Boolean
Dim i As Long
Dim x As Long
AddOrSubtract = HowManyWorkDays / Abs(HowManyWorkDays)
HowManyWorkDays = Abs(HowManyWorkDays)
If HowManyWorkDays = 0 Then
DateAddWorkDays = Format(StartDate, "mm/dd/yyyy")
Exit Function
End If
DateInQuestion = Format(StartDate, "mm/dd/yyyy")
Do Until CountOFWorkdays >= HowManyWorkDays
DateInQuestion = DateAdd("d", (1 * AddOrSubtract), DateInQuestion)
If (Weekday(DateInQuestion) <> 1) And (Weekday(DateInQuestion) <> 7) Then
For x = 0 To UBound(ListofHolidays)
If DateInQuestion = Format(ListofHolidays(x), "mm/dd/yyyy") Then
CountOFHolidays = CountOFHolidays + 1
isholiday = True
Exit For
End If
Next x
If isholiday = False Then
CountOFWorkdays = CountOFWorkdays + 1
Else
isholiday = False
End If
End If
Loop
DateAddWorkDays = DateInQuestion
End Function
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