by Pankaj Nagar (1 Submission)
Category: Windows API Call/Explanation
Compatability: Visual Basic 3.0
Difficulty: Advanced
Date Added: Wed 3rd February 2021
Rating: 
(4 Votes)
Using windows API SendMessage Call, this class Searches for a matching string in ListBox (In Association with a textbox) or ComboBox. And believe me its really Fast, Super Fast... ;-)
Inputs
ctlSource: The Source control (ComboBox or TextBox in case to search in ListBox)
str: The string to search (i.e.
Assumes
Usage:
' 1 - In the module declaration declare
Dim cBS As New clsBoxSearch
' 2 - Write on TextBox or ComboBox Keypress event
Private Sub cmbSearch_KeyPress(KeyAscii As Integer)
cBS.FindIndexStr cmbSearch, cmbSearch.Text, KeyAscii
End Sub
Private Sub txtSearchItem_KeyPress(KeyAscii As Integer)
cBS.FindIndexStr txtSearchItem, txtSearchItem.Text, KeyAscii, lstSearchName
End Sub
Code Returns
None: Just sets the ListIndex to the Found String
API Declarations'**********************************************************************
'Declaration for Search Routines in ListBox (LB) and ComboBox (CB)
Public Const LB_FINDSTRING As Long = &H18F
Public Const LB_FINDSTRINGEXACT As Long = &H1A2
Public Const CB_ERR As Long = (-1)
Public Const LB_ERR As Long = (-1)
Public Const WM_USER As Long = &H400
Public Const CB_FINDSTRING As Long = &H14C
Public Const CB_SHOWDROPDOWN As Long = &H14F
Public Declare Function SendMessageStr Lib _
"user32" Alias "SendMessageA" _
(ByVal hWnd As Long, _
ByVal wMsg As Long, _
ByVal wParam As Long, _
ByVal lParam As String) As Long
'***********************************************************************Option Explicit
Public Sub FindIndexStr(ctlSource As Control, _
ByVal str As String, intKey As Integer, _
Optional ctlTarget As Variant)
Dim lngIdx As Long
Dim FindString As String
If (intKey < 32 Or intKey > 127) And _
(Not (intKey = 13 Or intKey = 8)) Then Exit Sub
If Not intKey = 13 Or intKey = 8 Then
If Len(ctlSource.Text) = 0 Then
FindString = str & Chr$(intKey)
Else
FindString = Left$(str, ctlSource.SelStart) & Chr$(intKey)
End If
End If
If intKey = 8 Then
If Len(ctlSource.Text) = 0 Then Exit Sub
Dim numChars As Integer
numChars = ctlSource.SelStart - 1
'FindString = Left(str, numChars)
If numChars > 0 Then FindString = Left(str, numChars)
End If
If IsMissing(ctlTarget) And TypeName(ctlSource) = "ComboBox" Then
Set ctlTarget = ctlSource
If intKey = 13 Then
Call SendMessageStr(ctlTarget.hWnd, _
CB_SHOWDROPDOWN, True, 0&)
Exit Sub
End If
lngIdx = SendMessageStr(ctlTarget.hWnd, _
CB_FINDSTRING, -1, FindString)
ElseIf TypeName(ctlTarget) = "ListBox" Then
If intKey = 13 Then Exit Sub '???
lngIdx = SendMessageStr(ctlTarget.hWnd, _
LB_FINDSTRING, -1, FindString)
Else
Exit Sub
End If
If lngIdx <> -1 Then
ctlTarget.ListIndex = lngIdx
If TypeName(ctlSource) = "TextBox" Then ctlSource.Text = ctlTarget.List(lngIdx)
ctlSource.SelStart = Len(FindString)
ctlSource.SelLength = Len(ctlSource.Text) - ctlSource.SelStart
End If
intKey = 0
End Sub
VBcoders