by Peter B (1 Submission)
Category: String Manipulation
Compatability: Visual Basic 5.0
Difficulty: Beginner
Date Added: Wed 3rd February 2021
Rating: 
(2 Votes)
This code will search a string for a given starting point(strFind) and a given end point(strSentinel) and return all the text in between. You can also add to the length of the start point if you don't want to include a number of unknown characters in the result
VBcodersFunction ExtractString(ByVal strText As String, _
strFind As String, _
intAddToLen As Integer, _
strSentinel As String, _
TrapErrors As Boolean, _
intLength As Integer) As String
Dim SStart As Integer
Dim SEnd As Integer
SStart = InStr(1, strText, strFind) + Len(strFind) + intAddToLen
If SStart <= Len(strFind) And TrapErrors = True Then
MsgBox """" & strFind & """ not found!", vbCritical, "Error"
Exit Function
End If
SEnd = InStr(SStart, strText, strSentinel)
If SEnd <= Len(strFind) And TrapErrors = True Then
MsgBox "Sentinel value """ & strSentinel & """ not found!", vbCritical, "Error"
Exit Function
End If
If intLength > 0 Then
ExtractString = Mid(strText, SStart, intLength)
Else
ExtractString = Mid(strText, SStart, (SEnd - SStart))
End If
End Function
