by Jan Botha (6 Submissions)
Category: Math/Dates
Compatability: Visual Basic 3.0
Difficulty: Unknown Difficulty
Date Added: Wed 3rd February 2021
Rating: 
(3 Votes)
Use this module to do many calculations concerning dates. I will maybe add a few more later on.
This module inlcudes the following Functions:
1. DayOfWeek (Returns the day of the week of a certain date)
2. DayOfYear (Returns the day of the year, eg. 31 December 1999 will be 365)
3. DaysBetween (Returns the amount of days between two dates)
4. DaysInMonth (Retruns the days in a specified month, eg. 29 in February 2000)
5. DaysInYear (Returns the days in a specific year, eg. 365 in 1999)
6. IsLeapYear (Returns whether a year is a leap year)
Come on in, and take a look!!
Inputs
All the functions have different input parameters.
Assumes
Beginners will have to know how functions work. Basic knowledge, actually.
Code Returns
All the functions return something different
VBcoders'*************************************************
'*DATEFUNCTIONS *
'* *
'*By: Jan Botha *
'*eMail: [email protected] *
'*Date: Sunday, 19 September 1999 *
'*Inspired by David I Schneider's book, *
'* "An Introduction to Programming using *
'* Visual Basic 5.0 - Third Edition" *
'*I only got one of the formulas out from his *
'*book as well as the idea. As I programmed on *
'*I got ideas for other functions too. *
'*So here they are! *
'*************************************************
Option Explicit
'This returns the day of the week of a certain date.
'It will only work with dates after 1582, because
'the calendar we use today was introduced then
Public Function DayOfWeek(ByVal Day As Integer, ByVal Month As Integer, ByVal Year As Integer) As String
Dim w As Integer, wQuotient, wRemainder, int6
If Month = 1 Then
Month = 13
Year = Year - 1
ElseIf Month = 2 Then
Month = 14
Year = Year - 1
End If
int6 = 0.6 * (Month + 1)
int6 = Int(int6)
'I got this formula from David I Schneider's book
'"An Introduction to Programming using Visual Basic 5.0 - Third Edition"
w = Day + 2 * Month + int6 + Year + Int(Year / 4) - Int(Year / 100) + Int(Year / 400) + 2
wQuotient = Int(w / 7)
DayOfWeek = DayString(w - (wQuotient * 7))
End Function
'See what day of the year it is
Public Function DayOfYear(ByVal Day As Integer, ByVal Month As Integer, ByVal LeapYear As Boolean) As Integer
Dim i As Integer, fDay As Integer
For i = 1 To Month - 1
fDay = fDay + DaysInMonth(i, LeapYear)
Next
fDay = fDay + Day
DayOfYear = fDay
End Function
'This function check how many days there are between
'two certain dates
Public Function DaysBetween(ByVal startDay As Integer, ByVal startMonth As Integer, ByVal startYear As Integer, ByVal endDay As Integer, ByVal endMonth As Integer, ByVal endYear As Integer) As Long
Dim startIsLeap As Boolean, endIsLeap As Boolean
Dim daysToEnd As Integer, fDays As Integer
startIsLeap = IsLeapYear(startYear)
endIsLeap = IsLeapYear(endYear)
startDay = DayOfYear(startDay, startMonth, startIsLeap)
endDay = DayOfYear(endDay, endMonth, endIsLeap)
If startYear = endYear Then
DaysBetween = endDay - startDay
Exit Function
End If
daysToEnd = DaysInYear(startYear) - startDay
For i = startYear + 1 To endYear - 1
fDays = fDays + DaysInYear(i)
Next
fDays = fDays + daysToEnd + endDay
DaysBetween = fDays
End Function
Public Function DaysInMonth(ByVal Month As Integer, ByVal LeapYear As Boolean) As Integer
Select Case Month
Case 1, 3, 5, 7, 8, 10, 12: DaysInMonth = 31
Case 2
If LeapYear Then
DaysInMonth = 29
Else
DaysInMonth = 28
End If
Case 4, 6, 9, 11: DaysInMonth = 30
End Select
End Function
'Use this function to determine how many days there are in a year
Public Function DaysInYear(ByVal Year As Integer) As Integer
'leap years have 366 days and other years have
'365. simple
If IsLeapYear(Year) Then
DaysInYear = 366
Else
DaysInYear = 365
End If
End Function
Private Function DayString(ByVal Weekday As Integer)
'this function is used by the DayOfWeek function only
Select Case Weekday
Case 0: DayString = "Saturday"
Case 1: DayString = "Sunday"
Case 2: DayString = "Monday"
Case 3: DayString = "Tuesday"
Case 4: DayString = "Wednesday"
Case 5: DayString = "Thursday"
Case 6: DayString = "Friday"
End Select
End Function
' Use this function to determine if a certain year is a leap year.
Public Function IsLeapYear(ByVal Year As Integer) As Boolean
If Year Mod 4 = 0 Then
IsLeapYear = True
If Year Mod 100 = 0 And Year Mod 400 <> 0 Then
IsLeapYear = False
End If
End If
'all years divisible by 4 are leap years with the exception
'of years that are divisible by 100 and not by 400
End Function
Please email me comments, suggestions and especially BUGS!
[email protected]
