by Dave Pipkin (1 Submission)
Category: Math/Dates
Compatability: VB 6.0
Difficulty: Unknown Difficulty
Originally Published: Mon 19th November 2001
Date Added: Mon 8th February 2021
Rating: 
(1 Votes)
Converts a number from one base to another, can handle bases 2-36.
VBcoders
On Error GoTo ErrHandle
Dim conString As String
Dim i As Integer
Dim i2 As Integer
Dim tmp As String
Dim dig As String
'Check for invalid bases
If inBase < 2 Or inBase > 36 Or outBase < 2 Or outBase > 36 Then GoTo ErrHandle
'Check for zero value
If inNum = "0" Then GoTo ErrHandle
'Check for negatives and fractions and remove
If Left(inNum, 1) = "-" Then inNum = Mid(inNum, 2)
If InStr(1, inNum, ".") > 0 Then inNum = Left(inNum, InStr(1, inNum, ".") - 1)
'Capitalize
inNum = UCase(inNum)
'Check for hex prefixes
If LCase(Left(inNum, 2)) = "0x" Or LCase(Left(inNum, 2)) = "&h" Then inNum = Right(inNum, Len(inNum) - 2)
'String for all numbers up to base 36
conString = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"
'Convert to decimal
If inBase <> 10 Then
tmp = "0"
For i = Len(inNum) To 1 Step -1
dig = inBase ^ (Len(inNum) - i)
tmp = Val(tmp) + Val(InStr(1, conString, Mid(inNum, i, 1)) - 1) * Val(dig)
Next i
Else
tmp = inNum
End If
'Convert to outBase
If outBase <> 10 Then
If Val(tmp) < outBase Then
convertNum = Mid(conString, Val(tmp) + 1, 1)
Else
convertNum = ""
For i = 1 To 256
If outBase ^ i > Val(tmp) Then
i2 = i
Exit For
End If
Next i
For i = i2 To 1 Step -1
dig = outBase ^ (i - 1)
If Val(tmp) < Val(dig) Then
dig = "0"
Else
dig = Int(Val(tmp) / Val(dig))
tmp = Val(tmp) - Val(dig) * outBase ^ (i - 1)
End If
convertNum = convertNum & Mid(conString, Val(dig) + 1, 1)
Next i
End If
Else
convertNum = tmp
End If
Exit Function
ErrHandle:
convertNum = "0"
End Function
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